(8/27)^x=(4/9)^x

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Solution for (8/27)^x=(4/9)^x equation: 



(8/27)^x=(4/9)^x

We move all terms to the left:

(8/27)^x-((4/9)^x)=0



Domain of the equation: 27)^x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 9)^x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+8/27)^x-((+4/9)^x)=0

We calculate fractions


72^x)/27^x*9)^x))+(-108^x/27^x*9)^x))=0

We can not solve this equation

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